![Given that `sum_(n=1)^oo 1/n^2=pi^2/6 and sum_(n=1)^oo 1/(n^2+8n+16)=pi^2/a-b` where a in `N ... - YouTube Given that `sum_(n=1)^oo 1/n^2=pi^2/6 and sum_(n=1)^oo 1/(n^2+8n+16)=pi^2/a-b` where a in `N ... - YouTube](https://i.ytimg.com/vi/GA_KdA904fM/maxresdefault.jpg)
Given that `sum_(n=1)^oo 1/n^2=pi^2/6 and sum_(n=1)^oo 1/(n^2+8n+16)=pi^2/a-b` where a in `N ... - YouTube
Dr Tom Crawford on Twitter: "Happy Pi Day all! Here's my tribute to the world's favourite mathematical constant - a geometrical representation of the Basel Problem. The lines represent the terms in
Another Math - π^2/6 ≈ 1.644934066848226436472 The “Basel Problem” asks for the exact sum of the reciprocal square series: 1 + 1/2^2 + 1/3^2 + 1/4^2 + 1/5^2 + ... + 1/(n-1)^2 +
![sequences and series - A Geometric Proof of $\zeta(2)=\frac{\pi^2}6$? (and other integer inputs for the Zeta) - Mathematics Stack Exchange sequences and series - A Geometric Proof of $\zeta(2)=\frac{\pi^2}6$? (and other integer inputs for the Zeta) - Mathematics Stack Exchange](https://i.stack.imgur.com/tC7aY.png)
sequences and series - A Geometric Proof of $\zeta(2)=\frac{\pi^2}6$? (and other integer inputs for the Zeta) - Mathematics Stack Exchange
![Fermat's Library on Twitter: "PAPER An easy way to prove that 1+1/4+1/9+1/16+...=π^2/6 which Euler missed. READ HERE: https://t.co/Ew5UICLGY7 https://t.co/1ImaetzUpr" / Twitter Fermat's Library on Twitter: "PAPER An easy way to prove that 1+1/4+1/9+1/16+...=π^2/6 which Euler missed. READ HERE: https://t.co/Ew5UICLGY7 https://t.co/1ImaetzUpr" / Twitter](https://pbs.twimg.com/media/C9Z5j6VU0AAPvsU.jpg)
Fermat's Library on Twitter: "PAPER An easy way to prove that 1+1/4+1/9+1/16+...=π^2/6 which Euler missed. READ HERE: https://t.co/Ew5UICLGY7 https://t.co/1ImaetzUpr" / Twitter
![Sara Venkatraman on Twitter: "What I think is especially striking is that the sum over just the odd integers (shown below) is (pi^2)/8, which is more than half of (pi^2)/6 ... https://t.co/0Ww3c3SxVK" / Sara Venkatraman on Twitter: "What I think is especially striking is that the sum over just the odd integers (shown below) is (pi^2)/8, which is more than half of (pi^2)/6 ... https://t.co/0Ww3c3SxVK" /](https://pbs.twimg.com/media/EwfV3jqW8AQhyCH.jpg)